JSON.simple is a simple Java library for JSON processing, read and write JSON data and full compliance with JSON specification (RFC4627)
Содержание
- 1. Download JSON.simple
- 2. Write JSON to File
- 3. Read JSON to File
- References
- About the Author
- Comments
- Maven Dependency:
- CrunchifyJSONReadFromFile.java
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download-json-simple»>1. Download JSON.simple
2. Write JSON to File
3. Read JSON to File
References
About the Author
mkyong
Comments
I did exactly how you did in the code up here, but I keep getting this error:
Unexpected character (?) at position 0.
It is hard to guess, unless shown your source code here. Just tested and the code is working fine.
I thing you just copied the code.
and have not files that imported the top.
so you must have file like,
import org.json.simple.JSONArray;
this is a file located somewhere.
mkyong. Just wanted to say thanks for your articles. They are simple and clear, and they have benefited me very much.
Hey!
Really nice and easy tutorial, thanks a bunch 🙂
I have one problem though, when I read with the JSONParser, the java application keeps the file in use.
If one were using streams, you could close it, but I can’t find anything on how to “cut” the connection to the json file on the computer so I can delete, move or change its’ name.
Hello,
I have a question. Shouldn’t be the FileReader closed too? The same way as a FileWriter instance in example above?
In your example (Number :-2 ) :- you added data in this sequence , Name -Age -Message. but it will print data in this sequence :- Age- Name- Message.
Any reason? how do you enforce storing sequence as data adding sequence??
How can I write JSON with which there are multiple children e.g
“name” : “IR 1561-149-1”,
“name” : “IR 1561-149”,
I believe the best solution is to create a JSONArray that is called “children” with several “child” JSONObjects in it.
JSONArray list = new JSONArray();
Error: The Method add(String) is undefined for the type JSONArray
What will be the solution please help
make sure you’ve imported org.json.simple.JSONArray and not org.json.JSONArray
How can i pass the folder path in the JSON.
But when passing the path(“/latest/object/300000006637803/child/child_c ) to JSON it reading as “/latest/MetaData_c/300000006637803/child/MetaDataFieldsCollection_c”
part=new LinkedHashMap();
part.put(“id”,count);
part.put(“path”,”/latest/object/300000006637803/child/child_c);
part.put(“operation”,operation);
System.out.println(JSONValue.toJSONString(part));
consider i have Json file and i need to append more json data to it . how can i do it]
very helpful really great and simple example
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Last Updated on July 17th, 2017 by App Shah 40 comments
In this Java Example I’ll use the same file which we have generated in previous tutorial.
Maven Dependency:
Sample JSON file content:
CrunchifyJSONReadFromFile.java
Output:
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